Seawater Chemistry
I. Introduction
A. The composition of seawater can
be divided into suspended (also called particulate) and dissolved materials.
B. Salinity is the term used to describe the concentration of
inorganic, dissolved salts in seawater.
1. Unit = ppt or
o/oo (per mil) by weight
2. Average
for world's open ocean = 35 o/oo
3. Range "
" " "
= 34-37 o/oo
4. Seawater is
therefore 96.5% H2O and 3.5% salts
5. The boundary
between dissolved and particulate is an arbitrary one set at a size of
0.45 microns.
a. This is what's
called an "operational definition" in science, which is one that’s determined
by practical considerations. In this case the practical consideration is the
size of the holes in the filter paper used to filter the water sample. This is
a procedure agreed upon by scientists to carry out a particular measurement or
observation.
C. These dissolved ions
make seawater a good conductor of electricity, unlike pure
water. The higher the salinity of the
water the higher is its conductivity, so salinity is often determined by measuring
the electricial conductivity.
D. The dissolved
constituents of seawater can be divided into five broad categories:
1. Major
constituents
2. Minor and trace
components
3. Nutrients
4. Gases
5. Organics - not
part of the salinity
II. Major Constituents (Comprise about 99.7% of all the dissolved materials)
A. Elements:
1. Primary are
Cl- (55.04%) and Na+ (30.61%, which make up 85.65% of
all the dissolved constituents.
2. Adding the next
four most abundant (SO42-, Mg2+, Ca2+,
and K+) brings the total to > 99% of the salts.
3. Finally the last
5 (HCO3-, Br-, H3BO3,
Sr2+, F-) brings the total to > 99.99%.
4. Almost all of
the rest of the 92 naturally occurring elements are found in the ocean but they
only total to 0.01% of the TDS.
5. Although the other components are a very small %
of the dissolved materials, they are essential for life on Earth.
B. Learn the first seven
dissolved constituents, in order of decreasing abundance.
Constituent o/oo
Cl- 19.2
Na+ 10.7
SO42- 2.5
Mg2+ 1.3
Ca2+ 0.4
K+ 0.4
HCO3- 0.1
C. By careful analysis of water samples collected during the
Challenger expedition of the late 1800's it was discovered that all of the
major constituents occur everywhere in the same relative proportions even
though the amount of water in the mixture varies. These major solutes
are called conservative because their concentrations are stable
over time in the oceans. This means that
the ratios of these ions to one another are constant throughout most of
the ocean because the oceans are very well stirred.
1. For example,
from this list of constituents you can see that the ratio of the weight of
sodium to the weight of chloride is:
Na 10.556
-- = --------
= 0.556
Cl 18.980
a. No matter what
the salinity, this ratio remains unchanged if only H2O is added or
taken away from the solution.
2. The conservative
behavior of the major constituents doesn't hold true at the mouths of large
rivers and in estuaries because the local conditions can concentrate or dilute
the salt content.
a. In a humid
climate such as we have here the influx of freshwater with a composition
different from seawater dilutes the salts & decreases o/oo.
b. Estuaries in
arid regions such as Texas, often have very saline waters due to excessive
evaporation.
3. The conservative
behavior also doesn't hold around mid-ocean ridges where some exchange of
elements takes place.
4. Doesn't hold for
Ca2+ and HCO3- in places because of the
dissolution and precipitation of CaCO3 in tests of various
organisms.
5. In polar regions
freezing and melting of sea ice causes minor variations because sea ice
preferentially excludes salts.
6. And finally it doesn’t hold in virtually land-locked seas like the
Black and Baltic.
7. But in
most places and at most times the ratios are constant so if you determine
the concentration of only one of these constituents you can calculate the rest by
multiplying by these ratios.
a. Cl- is easy,
quick and cheap to determine so it's most often used.
b. For example, if the
chloride content (o/oo) is 18.980, we can multiply this number by the ratio we
calculated above to determine the o/oo of sodium.
c. It
is also quite easy to determine the salinity of a seawater sample by measuring Cl-
because the overwhelming proportion of the salinity consists of the major conservative
elements. The salinity can be calculated from that using this formula:
Chlorinity X 1.80655 =
Salinity
d.
Chlorinity is determined by a procedure called a Mohr titration involving AgNO3
as the titrant:
gms Ag*
Chlorinity
= 0.3285233 -------------
kg
seawater
* grams
of Ag required to precipitate all the halides in a 0.3285233 kg sample of
seawater
1) The
chemical method for doing this was derived for the Challenger expedition and is
still used today.
8.
These days salinity is measured by measuring the electrical conductivity of a
seawater sample. The conductivity is
directly proportional to the content of dissolved salts and can be, therefore,
parlayed into a salinity determination.
9. When seawater evaporates or is diluted by precipitation, only the
proportion of H2O changes so the proportions of these salts are
unchanged.
a. In
climates with an excess of evaporation over precipitation salinities get
higher; that is the total content of dissolved salts per kilogram of seawater
increases but the ratios of the major components to one another remain the
same. At the same time, in areas of
excessive precipitation over evaporation salinities decrease, while the ratios
remain the same.
b. What
do you get if you evaporate seawater?
1) If
you evaporate it to 1/2 of its original volume you get CaCO3 to
precipitate out.
2)
Evaporate to 1/5 and CaSO4.2H2O
3)
Evaporate to 1/100 and all the NaCl comes out
4)
Evaporate to dryness and get K and Mg chlorides and sulfates.
5) In
ancient times people extracted NaCl from seawater by a partial evaporation to
remove the CaCO3. Then they
drained off the remaining brine and evaporated it down to 1/100 of the original
volume to get the NaCl out. They had to be careful not to evaporate it all the
way to dryness or they would get the very bitter K and Mg salts.
III. Salinity variations in the open oceans
A. 34 - 37 o/oo is the
range and 35 o/oo is the average
1. Red Sea = 40-42
o/oo because there is little incoming fresh water and high evaporation.
2. Gulf of Bothnia
(off Finland) = 5 o/oo because of just the opposite situation
3. Completely
isolated seas and lakes can reach as high 250 o/oo if there is little influx of
fresh water and lots of evaporation. For example, the salinity of the Dead Sea
is about 240 o/oo, and the salt is mainly MgCl2.
B. Processes = EVAPORATION, PRECIPITATION, FREEZING
1. Evaporation
and freezing cause an increase in salinity because only the H2O
is removed from the seawater, the salts do not go along with the water.
a. Evaporation =
liquid to gas transition
b. Freezing =
liquid to solid transition
c. As a result the
proportion of salts in seawater increases and therefore the salinity increases
2. Precipitation
causes a decrease in salinity because rainwater contains very little in the way
of dissolved constituents and, therefore, merely dilutes the concentrations of
salts by increasing the proportion of H2O.
Example
I
35 grams salt
Starting salinity =
35 o/oo = -------------------
1000 grams seawater
This means the 1 kg
sample of seawater contains 35 grams of salt and 965 grams of H2O.
After 100 grams of H2O have been evaporated, the remaining sample
still contains 35 grams of salt but now it only contains 865 grams of H2O
for a total seawater sample weight of 900 grams. Therefore, the new salinity
is:
35 grams salt
New salinity = 35 o/oo =
-------------------
900 grams seawater
Clearly, this will
yield a larger number than the starting salinity because the denominator is now
a smaller number and the numerator has not changed. The new salinity is 38.9
o/oo.
Example
II
As a second
example, imagine starting with the same seawater sample,
35 grams salt
Starting salinity =
35 o/oo = -------------------
1000 grams seawater
but now assume it
rains and 100 grams of virtually pure rainwater is added to the sample. Our new
sample contains 35 grams of salt and 1065 grams of H2O for a total
seawater sample weight of 1100 grams. Therefore, the new salinity is:
35 grams salt
New salinity = 35 o/oo =
-------------------
1100 grams seawater
Clearly, this will
yield a smaller number than the starting salinity because the denominator is
now a larger number and the numerator has not changed. The new salinity is 31.8
o/oo.
C. Evaporation and
precipitation are by the far the major processes and their variations are
climatically controlled.
1. Where EVAP > PRECIP seawater salinities are higher
a. Around 20-30oN and 20-30oS
b. Coincides with
the world's great deserts
2. Where PRECIP
> EVAP seawater salinities are lower
a. Around the
equator and at higher latitudes
3. When we discuss
the relationship between oceans and climates you'll find out why these
conditions occur where they do.
D. At the poles freezing
plays a part in increasing salinity as mostly H2O goes into the ice
leaving a more concentrated salt solution behind.
E. These effects are
extremely important in influencing the vertical movement of water in the deep
oceans. Along with temperature
variations, these salinity variations generate the so-called thermohaline
currents that move because of the density differences caused by temperature and
salinity variations.
1. Increased
o/oo == increased density = sinks
Decreased o/oo ==
decreased density = rises
IV. Minor and trace components
A. Some lists put Sr, B,
and F into this category.
B. Many of these
components are non-conservative.
1. The ones which
are involved in biological processes.
2. Others which
vary because of chemical processes such as oxidation are also
non-conservative.
C. Usually called trace
constituent if it occurs in amounts < 1 ppm. For example the
concentration of Fe is 0.01 ppm:
0.01
grams Fe
--------------------------
1,000,000
grams seawater
D. Many minor and trace elements are
essential for the survival of organisms,
both in the sea and on land. Some of these elements (Fe, Mn, Mo, Zn, Co, Cu,
and V) are so rare that their concentrations are commonly described in terms
such as parts per billion (ppb). The precise roles of many of these elements in
organism metabolism have not been established.
V.
Nutrients - elements other than C, H,
and O that are required for the synthesis of organic matter and whose scarcity
can limit productivity. (Productivity
= production of organic carbon from inorganic carbon -- accomplished largely by
plants.)
A. The common
limiting nutrients in the oceans are nitrogen, phosphorus, and silicon. Most
marine plants can't use these in elemental form but must use the dissolved
forms indicated
1. N = nitrate (NO3-),
nitrite (NO2-), ammonia (NH4+)
2. P = phosphate
(PO43-)
3. Si = SiO2
B. The variations
of these components in seawater are large both vertically and horizontally. The
typical profile of nutrient concentrations in the ocean is to be seriously
depleted at the surface where photosynthesis is occurring the most rapidly. The
nutrient concentration increases with depth as creatures die and release their absorbed
nutrients back into the water column. The rate of nutrient increase decreases and
stops with depth as the sinking organic matter is completely dissolved. Irregularities
in the subsurface pattern of nutrient distribution are caused by variations in the
circulation patterns for water masses in the various oceans. Remember the
important link between biological activity and nutrient concentration.
VII. Dissolved Gases
A. The most
abundant gases dissolved in seawater are:
% in % in
surf. Water
Gas
dry air seawater Air
Solubility
Nitrogen 78 47.5 0.6
Lowest
Oxygen 21 36.0 1.7
Interm.
Carbon 0.03 15.1 500
Greatest
Dioxide
Ar, H, 1 1.4 1.5
Interm.
Ne, He
N2
O2 CO2
Typical
concentrations (ml/L) 10
5 40
B. This
should come as no surprise because these are common and important gases in our
atmosphere. But you can see that their relative concentrations in seawater
differ from their relative concentrations in the atmosphere. This is because of differing
solubilities. Just like solids have a
solubility in seawater, gases also have a solubility. CO2 is
extremely soluble in water. C. The concentration of nitrogen gas in
seawater is quite constant and has no biological implications.
D. On the
other hand, the concentrations of carbon dioxide (CO2) and oxygen (O2)
vary significantly from place to place in the ocean and their distributions are
significantly influenced by biological activity near the sea surface.
E. Oxygen
and carbon dioxide are intimately involved in photosynthesis and respiration. (Photosynthesis
is the production of organic matter
from inorganic carbon and respiration is the destruction of that organic matter
by reaction with oxygen gas.) Look again at the
photosynthesis equation. From this
equation you would predict that as photosynthesis occurs rapidly at the surface
carbon dioxide should be depleted and oxygen should be enriched. When the photosynthesizing organisms die and
sink down through the water column respiration occurs and photosynthesis
ceases. Organic matter that was generated at the surface reacts with oxygen at
depth and is reconverted to carbon dioxide and nutrients are released into the
water again. The concentration of carbon dioxide changes like the nutrients and
oxygen shows a distinct oxygen minimum
layer where respiration is most vigorous - consuming oxygen. The respiration is
performed either by the original plant or by organisms which have consumed the
materials produced by the plant. At
greater depth, there is less animal activity, less oxygen consumed, and fewer
nutrients released.
1. The
variation in available sunlight is the major factor, other than nutrient
availability, that determines the relative rate of photosynthesis and
respiration/decay. Sunlight only penetrates a few hundred meters down into the
ocean (even in the clearest, cleanest water, such as that found in the centers
of the oceans, far from the continents).
a. PSYN is not
fastest right at surface because many marine plants can't deal with such high
levels of sunlight, instead most photosynthesize most efficiently a few inches
below the surface.
b. At some point,
however, the sunlight levels decrease so much that the rate of PSYN begins to decrease
and is eventually overwhelmed by the rate of respiration which returns
nutrients and dissolved carbon to the oceans and uses up oxygen.
c. Respiration is
at a maximum in the OXYGEN MINIMUM ZONE
2. The CO2
profile is similar to the nutrient profiles because it is used up during PSYN
just like the nutrients are.
3. The nutrient
concentration increases with depth as creatures die and release their
absorbed nutrients back into the water column.
a. The rate
of nutrient increase decreases and stops with depth as the sinking
organic matter is completely dissolved.
b. Later, you will
learn about an important process called upwelling that returns
these dissolved nutrients to the surface water where they can be utilized anew
by marine plants. Without upwelling, it
is estimated that the seas would be dead within a year after it stopped.
4. The oxygen
profile is a mirror image of the CO2 profile because it is produced
while CO2 is consumed.
F. The large solubility
of CO2 in water has extremely important implications for life in the
oceans and all over the surface of the Earth.
1. Many life forms
in the sea are dependent on dissolved CO2 gas as a source of
carbonate to make their CaCO3 shells and tests.
2. CO2
plays another and extremely important role in the ocean: in water it acts as a pH
buffer. A buffer prevents sudden, extreme changes in the acidity or
alkalinity (i.e., the pH) of water. Such rapid changes would be fatal for most
marine organisms.
3. Finally, CO2's
extreme solubility makes life on the surface of the Earth possible by removing the
primary insulating "Greenhouse gas" from our atmosphere, thereby
keeping the temperature at the surface of the Earth at a livable level.
VIII. Dissolved organics
A. Not part of salinity
B. Fats, proteins,
carbohydrates, hormones, vitamins, etc.
C. Occur in low concentrations (?)
IX. Movement of materials in seawater
A. Mostly pretty well-mixed
due to wind, waves, surface and thermohaline currents which move material by convection that is by moving the water itself.
B. Diffusion
which is the movement of the individual atoms and molecules is extremely slow
and by itself could not possibly create a well-mixed solution.
X.Origin
of Earth’s surface water and its components
A. The fossil and
sedimentary rock records indicate that the oceans were present as far
back in time as at least 3.4 billion yrs. Prior to that time the Earth
was too hot for liquid water to be stable on its surface and the vaporized H2O
was lost to outer space.
B. After the Earth
cooled enough to permit liquid water to accumulate, volcanic emanations
provided a steady supply which eventually filled up the ocean basins. The solidification of what was once a mostly molten planet resulted in the
separation of the more volatile components (water, HCl gas, CO2 gas,
etc.) from the less volatile components
such as Fe, Mg, Si, etc. These volatile components are naturally quite light and rise
towards the surface of the Earth.
1. Process often
called outgassing.
2 Measurements of the current rate
of outgassing during volcanism yield rates that can account for the total
amount of surface water we observe today given 3 billion years for it to accumulate.
3. Also measurements of the amounts of these
volatile substances trapped in bubbles in solidified igneous rock show that
they contain these volatiles in about the correct abundances to explain the
surface abundances.
4. Volcanic emanations
provided the following elements to the original ocean:
S C Cl
Br N
Sulfur, Carbon,
chlorine, bromine, and nitrogen gases.
C. The nonvolatile
elements: (e.g. Na, Mg, Ca, K) came from rain moving over and through
rocks on the continent, dissolving constituents from those rocks and carrying them
down to the oceans in the rivers.