1.  Safety
2.
Objectives/Overview
3.
Procedures
4.
Observations
5.

Equipment

6.

View Techniques

7.

Waste Disposal/Clean-up

8. Conclusions
9. Calculations/Set-Ups
10. Grading Scale 
11. Review Prelab Questions
12.
Review Postlab Questions

Experiment 14
Using Freezing Point Depression to Find Molecular Weight

OBJECTIVES/OVERVIEW

When a solute is dissolved in a solvent, the freezing temperature is lowered in proportion to the number of moles of the solute added. This property, known as freezing point depression, is a colligative property;that is, it depends on the ratio of solute and solvent particles, not on the nature of the solute itself. Equation (1) below shows this relationship:

ŠT = Kfm

where ŠT is the freezing point depression, Kfis the freezing point depression constant for a particular solvent (2.72°C kg/mol for lauric acid in this experiment), and m is the molality of the solution.

Molity has units of
mol solute
kg solvent

In this experiment, you will first find the freezing temperature of the pure solvent, lauric acid (dodecanoic acid), CH3(CH2)10COOH. You will then find the freezing point of a mixture of lauric acid and an unknown solute, such as acetic acid, CH3COOH. By measuring the freezing point depression, ŠT, and knowing the masses of solute and solvent, you can use equation (1) above to find the molecular weight (molar mass), in g/mol, of the unknown solute.

Your instructor will assigning students to work together in teams of two. In order to work efficiently, students should divide the work in such a way that efforts are not being duplicated. For example, one partner can set up the beaker of water while the other partner weighs the lauric acid. Both partners should observe the temperature changes as the substance cools.

 

 
 
 
 
 

 

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